3t + 7 = 2t - 5 3t = 2t - 12 t = -12
-2t = -10
Without an equality sign the given expression can't be considered to be an equation and so therefore no solution is possible.
2t+3 = -11 Subtract 3 from both sides: 2t+3-3 = -11-3 2t = -14 Divide both sides by 2 in order to find the value of t: t = -7
5t + 2 = 3t - 2t + 5 Collect like terms 5t - 3t + 2t = 5 - 2 4t = 3 t = ¾ Check: 5 x 3/4 = 3¾ + 2 = 5¾; 3x¾- 2x¾ + 5 = 5¾ QED
19-2t = 7 -2t = 7-19 -2t = -12 t = 6
3t + 7 = 2t - 5 3t = 2t - 12 t = -12
It is not possible to solve a single linear equation in two unknown variables (b and t).
An equation?
-2t = -10
A linear equation has no higher powers than 1. This is linear.
Rearranging the the equation to make c the subject:- c = kVp-2t
To me, this looks solved but of you want it in parametrics, y = -3 +2t (teR)
Without an equality sign the given expression can't be considered to be an equation and so therefore no solution is possible.
t - 2t - 3t = 32t - 5t = 32-4t = 32t = -8According to the information given in the question, t can't equal 8.
2t+3 = -11 Subtract 3 from both sides: 2t+3-3 = -11-3 2t = -14 Divide both sides by 2 in order to find the value of t: t = -7
To me, this looks solved but of you want it in parametrics, y = -3 +2t (teR)