5x+3 = x+4 5x-x = 4-3 4x = 1 x = 1/4 Thats not even close to how you solve it. First of all the equation is written 5^(x+3)=x+4. Simple Logarithms are needed to solve.
3x + 2x = 5x. 5x= (-4) X = (-4)/5 x= -0.8
did u mean y - 5 = 4?If u meant that, then y = 4 + 5 = 9
5t + 2 = 3t - 2t + 5 Collect like terms 5t - 3t + 2t = 5 - 2 4t = 3 t = ¾ Check: 5 x 3/4 = 3¾ + 2 = 5¾; 3x¾- 2x¾ + 5 = 5¾ QED
(20 - x)/5
3
3
3
-2+5=3
2x+4-x = 4x-5 2x-x-4x = -5-4 -3x = -9 x = 3
u = 7 + 2 + (4 - 5) = 9 + (-1) = 8
minus 5
-2 + 5 = xsame as:5 - 2 = xx = 3
5 + (-4) = 1 x = -4
4 + 4 +1
-5(3n plus 4) 40 is a set of disjointed expressions: it is not a formula and so cannot be solved.
3x+5=4-2x+6 5x=4-1 5x=3 x=3/5