3x+5=4-2x+6
5x=4-1
5x=3
x=3/5
Collect the like terms;42x-23 = 940Add 23 to both sides;42x = 963Divide both sides by 42;x = 963/42
-1/19=x
To solve ((3x + 7)^2), you can use the formula for squaring a binomial, which is ((a + b)^2 = a^2 + 2ab + b^2). Here, (a = 3x) and (b = 7). Applying the formula gives: [ (3x + 7)^2 = (3x)^2 + 2(3x)(7) + 7^2 = 9x^2 + 42x + 49. ] So, ((3x + 7)^2 = 9x^2 + 42x + 49).
23
x=7
Collect the like terms;42x-23 = 940Add 23 to both sides;42x = 963Divide both sides by 42;x = 963/42
-1/19=x
It is 14*(3x + 2y)
3
23
x=7
x = -8
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
-3x + 5 = 20 -3x = 15 x = -5
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
If that's +42x + 49, the answer is (3x + 7)(3x + 7) or (3x + 7)2 If that's -42x + 49, the answer is (3x - 7)(3x - 7) or (3x - 7)2
x = -8