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I am not sure what the question is, but heres my 2 cents.

You know what? Never mind. I don't get the question at all. In order to use substitution, you must totally isolate a variable to 1 side, and only have the variable on 1 side. Then you substitute it. Ex:

2y+4x-5z=45

2z+x-4y=54

Isolate x in the 2nd equation, as it is easier:

x=54-2z+4y

Now, substitute it:

2y+4(54-2z+4y)-5z=45

Got it? I might have done something wrong.

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16y ago

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Q: How do you solve this system of equations using substistution x-y12 x y3?
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