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How do you solve this using the system of substitution y quals -3x 5 and 5x-4y equals -3?
Simply take the first equation and substitute it for y in the second one.
We're told:
y = -3x + 5
and:
5x - 4y = -3
So we can say:
5x - 4(-3x + 5) = -3
5x + 12x - 20 = -3
17x = 17
x = 1
Then plug that value into one of our original equations to solve for y:
y = -3x + 5
y = -3(1) + 5
y = 5 - 3
y = 2
So the two equations intersect at the point (1, 2).
What else can I help you with?
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You'd need another equation to sub in
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elimination, substitution and graphing
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True. To solve a three variable system of equations you can use a combination of the elimination and substitution methods.
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How do use substitution when solving system of equations?
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In that instance, it means that the lines never touch.
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2
How do you solve by substitution y equals x-1?
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