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Without any equality signs they can't be considered to be equations. But if you mean: x+2y =12 and y = x+3 then the solution is as follows x+2y = 12 -x+y = 3 Adding the equations together: 3y = 15 and y = 5 By substitution: x = 2 Solution: x = 2 and y = 5
Say you have a pair of equations like a+b=1 and 2a+3b=5. To solve using substitution you would set one equation against one variable (say a=1-b) then plug that into the other (2(1-b)+3b=5), then solve for the one variable you have there and then plug that result into the other equation (in this case b=3 and a=-2).
To solve this question use a two variable system of equations. First assign a variable to each number: a=first number b=second number Then use the information in the problem to write two equations They have a product of 20 translates to: a x b =20 They have a sum of 9 translates to: a + b =9 Use the method of substitution. Isolate one variable in the 1st equation: a= 20/b Plug it into the 2nd equation: (20/b) + b = 9 Solve for b: b = 5 Now put b back into the 2nd equation: a + 5=9 Solve for a: a = 4 So the solution is 4 and 5.
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2x + 5y = 2-3x - y = -3from the second equation:-y = -3 + 3xy = 3 - 3xsubstitute this value in the first equation:2x + 5(3-3x) = 22x + 15 - 15x = 2-13x + 15 = 2-13x = 2 - 15-13x = -13so, x = 1Now, solve for y :y = 3 - 3xy = 3 - 3 (1)y = zero