Square the two smaller sides and add them together. Take the square root of the answer. If that is the same as the third side then you have a right angled triangle and if not, then you have not.
Two sides, or two angles + one side.
I assume that you mean that you are given a differential equation dy/dx and want to solve it. If that is the case, then you would multiply by dx on both sides and then integrate both the left and right sides of the equation.
Use the sine rule to work out one of the sides. (a/sina = b/sinb = c/sinc) Then as it is an isosceles triangle the perpendicular dropped from the apex will (a) bisect the base and (b) form a right angle with the base. Now you know one side and the hypotenuse of a right-angled triangle and you use Pythagoras (a2 + b2 = c2) to solve the 'other' side of that, which is the height of the isosceles triangle.
First, get the radical by itself. Then, square both sides of the equation. Then just solve the rest.
ok, i figured it out. the length of the triangle is 5, 4, 3. the four is 1/2 the length of one side of the rectangle. so the rectangle sides are 8, 8, 3, 3 (one three being one side of the rectangle as well)
It depends on the details of the specific triangle.
Two sides, or two angles + one side.
Given the lengths of two sides of a right triangle, you can find the length of the other side.
You will also need the angles so that you can use the Isosceles Triangle Theorems to solve for the base of isosceles triangle when only two sides are given.
A right triangle has three sides. If you label the sides connected to the right angle side A and side B, and the hypotenuse side C, A^2+B^2=C^2.
you must have at least 2 given sides or a given angle you can use the pythagorean theorem formula c² = a² + b² try the link below for a computation
Make it a right triangle where one side of the right triangle is half the length of the non-identical side of the isosceles, the hypotenuse of the right triangle is the length of one of the identical sides of the isosceles triangle, then use the Pythagorean theorem. a^2+b^2=c^2. Where "a" is the length of one of the identical sides, and "c" is the length of half the non-identical sides. Solve for "b" and that is your height.
true
By using the cosine rule in trigonometry the angles of the triangle can be worked out.
If it is a right triangle, you can use the Pythagorean theorem to find the height since it will be on of the sides. If it is an equilateral triangle, you can break it up into two right triangles and use the part above. If it is an oblique triangle, you use the angles and some trigonometry to find it. Since the area is 1/2 b x h, if you are given the area, you can solve for the height.
You use the Pythagorean theorem, which can only be applied to right triangles: a2+b2=c2, where a and b are the triangle's legs and c is the triangle's hypotenuse. Plug the two sides you know into the equation, then solve for the unknown side.
Proportions would be the best way; given the sides of the triangle, use ratios to find the corresponding side on the congruent triangle. For example: if three sides are given, 3, 4, and 5, and you had to solve a triangle with lengths 9, 12, and x, this is how you would do it. Given the triangles are congruent, 4/5 = 12/x 4x = 60 x = 15