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How do you find the height of an isosceles triangle when given only the three side lengths?
Make it a right triangle where one side of the right triangle is half the length of the non-identical side of the isosceles, the hypotenuse of the right triangle is the length of one of the identical sides of the isosceles triangle, then use the Pythagorean theorem. a^2+b^2=c^2. Where "a" is the length of one of the identical sides, and "c" is the length of half the non-identical sides. Solve for "b" and that is your height.
How do you solve an isosceles triangle?
It depends on the infoamtion that you have.
If two sides of a triangle are congruent then the angles opposite those sides are?
Correct as would be the case for an isosceles triangle or an equilateral triangle
How do you construct an isosceles triangle when base and angle at the vertex is given?
First find 180 minus the vertex angle and divide that by 2 to get the other angles. Then solve the other sides by using sin(vertex angle)/base=sin(other angles)/other sides.
What does it mean to ''solve a triangle''?
It means to find all of its sides and angles.
How do you find the height of an isosceles triangle when given only the three side lengths?
Make it a right triangle where one side of the right triangle is half the length of the non-identical side of the isosceles, the hypotenuse of the right triangle is the length of one of the identical sides of the isosceles triangle, then use the Pythagorean theorem. a^2+b^2=c^2. Where "a" is the length of one of the identical sides, and "c" is the length of half the non-identical sides. Solve for "b" and that is your height.
How do you solve an isosceles triangle?
It depends on the infoamtion that you have.
How can you solve for angle A given a right triangle when two sides are given in trigonometric functions?
It depends on the details of the specific triangle.
If two sides of a triangle are congruent then the angles opposite those sides are?
Correct as would be the case for an isosceles triangle or an equilateral triangle
Height of an isosceles triangle?
If you know the length of the sides, you can use Pythagoras' Theorem to calculate the height. Use half the base for one of the shorter sides, and either of the two identical sides of the triangle for the hypothenuse. Solve for the other one of the shorter sides (the height).
How do you construct an isosceles triangle when base and angle at the vertex is given?
First find 180 minus the vertex angle and divide that by 2 to get the other angles. Then solve the other sides by using sin(vertex angle)/base=sin(other angles)/other sides.
How do you solve a Pythagoras problem when the two shorter sides are both unknown?
You cannot - unless there is some other information. For example, that the triangle is isosceles, or that one of the shorter sides is related to the other is some way. Or there is another triangle (or other shape) from which you can work out one of the sides.
Which is enough given information needed to solve a right triangle?
Two sides, or two angles + one side.
What can you solve in the Pythagorean theorem?
Given the lengths of two sides of a right triangle, you can find the length of the other side.
How do you solve to find a right triangle of you are given three sides?
Square the two smaller sides and add them together. Take the square root of the answer. If that is the same as the third side then you have a right angled triangle and if not, then you have not.
You know base and angles how do I find height of isosceles triangle?
Use the sine rule to work out one of the sides. (a/sina = b/sinb = c/sinc) Then as it is an isosceles triangle the perpendicular dropped from the apex will (a) bisect the base and (b) form a right angle with the base. Now you know one side and the hypotenuse of a right-angled triangle and you use Pythagoras (a2 + b2 = c2) to solve the 'other' side of that, which is the height of the isosceles triangle.
Is this statement true or falseYou can use the Law of Cosines to solve a triangle when you are given the lengths of the three sides and no angle measures?
true
