You need to factor it.
x2+x-12=0
(x+4)(x-3)=0
x+4=0, x-3=0
x=-4, x=3
You can also use the quadratic formula, but factoring is easier when it's possible.
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12 squared plus 18 squared is equal to 468.
a2 + 62 = 122 a2 + 62 - 62 = 122 - 62 a2 = 144 - 36 a2 = 108 taking the square root of each side, we get a equal plus or minus the square root of 108, or plus or minus 6 times the square root of 3.
In such cases, there is usually a discontinuity when the denominator is zero. In other words, solve for:x + 2 = 0
The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)
answer is p/5. problem: {[(p^2)-3p]/[(p^2)-6p+9]}/{20/(4p-12)}