You need to factor it.
x2+x-12=0
(x+4)(x-3)=0
x+4=0, x-3=0
x=-4, x=3
You can also use the quadratic formula, but factoring is easier when it's possible.
12 squared plus 18 squared is equal to 468.
a2 + 62 = 122 a2 + 62 - 62 = 122 - 62 a2 = 144 - 36 a2 = 108 taking the square root of each side, we get a equal plus or minus the square root of 108, or plus or minus 6 times the square root of 3.
In such cases, there is usually a discontinuity when the denominator is zero. In other words, solve for:x + 2 = 0
The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)
answer is p/5. problem: {[(p^2)-3p]/[(p^2)-6p+9]}/{20/(4p-12)}
133
(x + 12)(x - 3)
(x - 5)(x + 12)
z2 - 12 + 36 is the same as z2 + 24. That's a simplification, but not a solution. There's nothing to solve, because the question doesn't give an equation. If z2+24 were equal to something, then we'd have an equation, and we would be thrilled to solve it for the value of 'z'.
-22 - 12 = -8
X=-3
15x minus 8=minus 180 3x+8=24
12 squared plus 18 squared is equal to 468.
It is x^2 -13x +12 = (x-1)(x-12) when factored
(6x - 1)(6x - 1)
Let square = [x] -4+3*(-2)*[-4]+[3x-2x]=-4-6-2+[x]=-12+[x]The answer is negative 12 plus squared x.
a2 + 62 = 122 a2 + 62 - 62 = 122 - 62 a2 = 144 - 36 a2 = 108 taking the square root of each side, we get a equal plus or minus the square root of 108, or plus or minus 6 times the square root of 3.