49x2 - 84x + 36 = (7x - 6)(7x - 6) or (7x - 6)2
x^(2) - 12x + 36 Look for two factors of '36', that add/subtract to '12'. ;- 1,36 ; 2,18; 4,9; 6,6. The last pair 6 & 6 add to ;12; Hence (x 6 )(x 6) Which signs???? Since '36' is positive(+), then both the signs are the same. They can be both negative , or both positive. Since the sign in '12x' is hegative then they are both negative. Hence (x - 6)(x - 6) Done!!!!!
x(x2 + 36)
(x - 6)(x^2 + 6x + 36)
(x + 4)(x + 9)
x sq equalls 36 and x equalls plus or minus 6
(6x - 1)(6x - 1)
49x2 - 84x + 36 = (7x - 6)(7x - 6) or (7x - 6)2
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
x2-5x-36 = (x-9)(x+4) when factored
x = plus or minus 6.
4(y - 3)(y + 3)
(x + 6)(x - 6)
(5x - 6)(5x + 6)
(x-4)
x2 + 36 cannot be factored. You can only factor the difference of two squares, not the sum.
(5w-6)2