First, solve for zero
y2 - 4y > 5
y2 - 4y - 5 > 0
(y - 5)(y + 1) > 0
So where y = 5 and y = -1, the inequality solves for zero. We know that because the term with the highest power of y has a positive coefficient, that this is a parabola which has a limit in the negative, and is infinite in the positive. That means y is less than negative one or greater than 5.
{x | x < -1 OR x > 5, x ∈ ℜ}
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This is called an inequality. If x squared is greater than or equal to 49, then x is plus or minus 7 or greater than plus 7 or less than - 7.
Since the question refers to "how much greater" rather than "how much as great as", the answer is that: t squared is (t-1) times greater than t.
You don't. There's no question there, and nothing that needs solving. "16 less than x squared" is written as (x2 - 16)
no - nor less than minus 1.
Yes. (If you subtract -17 minus -18 on a calculator, you get a positive number.)