A formula for the volume is (area of base)(height)/3. The base is a circle, with area equal to pi X radius squared. It was not specified whether the given "3 Cm" for the base was radius or diameter. After clarifying that, you should be able to complete the answer for yourself.
The volume is 1,900 units3
volume_of_prism = area_of_base x height 275 cm3 = 25 cm2 x height => height = 275 cm3 / 25 cm2 = 11 cm
If it is a right cone, then by Pythagoras,(Slant height)2 = 52 + 11 = 25 + 1 = 26 inches2So slant height = sqrt(26) inches = 5.099 inches = 5.10 inches (to 2 dp)If it is a right cone, then by Pythagoras,(Slant height)2 = 52 + 11 = 25 + 1 = 26 inches2So slant height = sqrt(26) inches = 5.099 inches = 5.10 inches (to 2 dp)If it is a right cone, then by Pythagoras,(Slant height)2 = 52 + 11 = 25 + 1 = 26 inches2So slant height = sqrt(26) inches = 5.099 inches = 5.10 inches (to 2 dp)If it is a right cone, then by Pythagoras,(Slant height)2 = 52 + 11 = 25 + 1 = 26 inches2So slant height = sqrt(26) inches = 5.099 inches = 5.10 inches (to 2 dp)
.11 base 10 is approx (0.00011100001) base 2
56.08921465 or about 56 square units Worked out by using Pythagoras' theorem and area = 1/2*base*height.
A cone with a base radius of 6 units and a height of 11 units has a volume of 414.69 cubic units.
The volume of a cone, if the height is 11 yd and the radius is 7 yd, is 564.44yd3
Volume = 323.57357 units3
Volume = 287.97933 units3
Volume is 103.7 units3
The volume is 1,900 units3
The volume of a cone is 1/3Bh. 1/3(49pi)(11) is approximately 564.4394 u.2.
1/3 x 32 x pi x 11 = 103.67cm3
104un3 Formula for volume of a cone V = (1/3)(pi)r2h = (3.14159.../3)(32)(11) = (1.047...)(9)(11) = 103.67...
A right circular cone with a radius of 6 cm and a height of 11 cm is a three-dimensional geometric figure that tapers smoothly from a circular base to a single point called the apex. The volume of this cone can be calculated using the formula ( V = \frac{1}{3} \pi r^2 h ), which gives approximately 132 cubic centimeters. The slant height can be found using the Pythagorean theorem, resulting in a slant height of about 13 cm. This cone is characterized by its circular base and the straight line segment connecting the apex to the edge of the base.
For a right circular cone: Vol. of cone = (PI*r2*h)/3 Vol. = (PI*(9)2*(11))/3 Vol. approx. = 933.1 cubic units
A cone 11 inches high by 4 inches in diameter has a volume of 46.08 cubic inches.