if y = x^a, then logxy = a
The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)
ln 60 = a
10^a=300.. apex!
c=3^27
Log=ea 47.38
A basic logarithmic equation would be of the form y = a + b*ln(x)
A logarithmic equation would be any equation that includes the log function.
I don't see an equation. An equation must have an equal sign. For a question in answers.com, you'll have to write the word "equals", since symbols get lost.
You can take the logarithm on both sides of an equation. The real trick is to figure out when this will help you to solve the equation, and when not.
The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)
Logarithmic equation
To convert ( a(x-2) ) to logarithmic form, you first need to isolate the expression. If you have an equation of the form ( a(x-2) = b ), you can rewrite it as ( x-2 = \frac{b}{a} ). Then, to express it in logarithmic form, you would take the exponential form ( a^{\log_a(b)} = b ) to find the corresponding logarithmic expression. If you need a specific logarithmic conversion, please clarify the context of ( a(x-2) ).
10a = 478
ln 60 = a
If by "real life" you include the physical world, then you express the spontaneous decay of radioactivity in a sample with a logarithmic equation.
y = b^x
If the equation was ln(x) = 2.35 then x = 10.4856, approx.