10a = 478
You can take the logarithm on both sides of an equation. The real trick is to figure out when this will help you to solve the equation, and when not.
The Answers community requires more information for this question. Please edit your question to include more context. c in 4 is not a logarithmic, nor any other sort of equation.
There are many equations that are neither linear nor quadratic. A simple example is a cubic equation, such as y = x3, or a logarithmic equation, such as y = ln(x).
Log 200=a can be converted to an exponential equation if we know the base of the log. Let's assume it is 10 and you can change the answer accordingly if it is something else. 10^a=200 would be the exponential equation. For a base b, we would have b^a=200
The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)
Logarithmic equation
A basic logarithmic equation would be of the form y = a + b*ln(x)
10a = 478
ln 60 = a
If by "real life" you include the physical world, then you express the spontaneous decay of radioactivity in a sample with a logarithmic equation.
if y = x^a, then logxy = a
y = b^x
If the equation was ln(x) = 2.35 then x = 10.4856, approx.
10^a=300.. apex!
c=3^27
You can take the logarithm on both sides of an equation. The real trick is to figure out when this will help you to solve the equation, and when not.