The shadow:object ratio is 1:1 so the tree is 63 feet high.
488 cm
27.3 feet
If the tree is T ft high, then T/21 = 8/3 so that T = 21*8/3 = 56 feet.
25 meters because 25/20 = 15/12 which is the tangent ratio.
The shadow:object ratio is 1:1 so the tree is 63 feet high.
Since the tree is twice as high as the length of the shadow, we can set up the following equation: 2x = x + 8, where x is the length of the shadow. Solving the equation gives us x = 8 feet, so the length of the shadow that the tree casts is 8 feet.
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
40 ft
50 feet
15 feet high
Not enough information has been given to solve this problem such as: What is the angle of elevation?
It works out as 12 feet and 4 inches in height
The man is twice as high as his shadow. Therefore, the tree must also be twice as high as its shadow, which would make the tree 40 feet tall.
A tree casts a large shadow.
The height of the tree is in direct proportion to the pole and its shadow
(12 / 5) × 33 = 79.2 feet high Divide the pole shadow by the pole height: (12 / 5) = 2.4 feet Times the 2.4 by the tree shadow of 33 feet: 2.4 x 33 = 79.2