The height of the tree is in direct proportion to the pole and its shadow
It works out as 12 feet and 4 inches in height
We can solve this problem using a ratio. Since a 6 foot man casts a 4 foot shadow we can write this ratio as 6:4. If we reduce this ratio we get 3:2. Now we're stating that for every 3 feet of height, the shadow cast will be 2 feet.Now we can work our problem out using a small table:3 feet of flag pole = 2 feet of shadow6 feet of flag pole = 4 feet of shadow9 feet of flag pole = 6 feet of shadow12 feet of flag pole = 8 feet of shadow15 feet of flag pole = 10 feet of shadow18 feet of flag pole = 12 feet of shadowTherefore an 18 foot flag pole will cast a 12 foot shadow at the same time that a 6 foot man casts a 4 foot shadow.
The tree is 25 feet tall. A 5 foot pole cast a 2 foot shadow. This means that the sun angle causes the shadow to be 2/5 the length of the object casting it. The tree's shadow is 10 feet tall. Multiply 10 feet by 5/2 (inverting the fraction because we're going the other way) and we get 25 feet.
Required angle has a tangent of 7.6/6.1 ie 1.249. This is 51.25 degrees.
Let x = the height of the building. So we have, x/2.6 = 42.25/1.51 x = (2.6)(42.25)/1.51 x =72.75 Thus, the building is 72.75 meter tall.
If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.
It is 90 feet in height
6 feet
25 feet tall
40 meters
3
(12 / 5) × 33 = 79.2 feet high Divide the pole shadow by the pole height: (12 / 5) = 2.4 feet Times the 2.4 by the tree shadow of 33 feet: 2.4 x 33 = 79.2
2
The shadow:object ratio is 1:1 so the tree is 63 feet high.
17.45 feet.
15 feet high
It works out as 12 feet and 4 inches in height