How is a y intercept of 5 written?
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y = slope*x + intercept, so y = -8x + 5
In the straight line equation of y = 3x+5 the slope is 3 and the y intercept is 5
y = 2x + 5At the y-intercept, x=0.y = 0 + 5y = 5
Then the straight line equation is y = 6.4x+.5 whereas 6.4 is the slope and .5 is the y intercept
y= slope + y-intercept