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The equation of the line can be written in slope-intercept form as y = 5x - 3. The slope is 5 and the y-intercept is -3, so the equation represents a line that has a slope of 5 and intersects the y-axis at -3.
y = 5x - 3
-1
The equation in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Given the slope m = 2 and the point (4, 2), plug in these values to find the equation: 2 = 2(4) + b. Solve for b to get b = -6. Therefore, the equation of the line is y = 2x - 6.
m stands for "modulus of slope"; modulus means "number used to measure." We now call the slope just simply "slope" but still use "m" to indicate it in the formula.
The slope of a line passing through two points (x1, y1) and (x2, y2) is given by the formula: (y2 - y1) / (x2 - x1). Using the points (0, -4) and (-6, 7), the slope is: (7 - (-4)) / (-6 - 0) = 11 / -6 = -11/6.
The slope of a line containing the points (1,3) and (2,5) is 2. This basic problem in graphics has a simple solution. The slope of a line is defined as the change in the y value divided by the change in the x value. Another way to express this is say "the rise over the run" of the line. Let's look at this line and find that "rise over run" for it. You can see the two coordinates, and the change in the y value from one to the next is from 3 to 5. That's a change of +2. The change in the x value for the same interval is from 1 to 2. That's a change of +1. To finish, +2/+1 = +2, and the slope of the line is 2. If we went the "other way" to solve it, had better work, hadn't it? Yes, it should. The change from 5 to 2 is a change of -3, which is the change in y value. The x value changes from 2 to 1, and that's a change of -1. Now we take the -2/-1 and resolve it and lo! it's +2, and the slope of the line is 2 just as it was before.
y = 2x + 1.
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
There is no slope nor intercept because there is no equation, simply an expression.
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
The equation of a line with an undefined slope is x = a.
It shows the relationship of y in terms of x. [y = (yIntercept) + ((slope)*(x))] [slope = (y2 - y1)/(x2 - x1)]
Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
you say undefined
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if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).