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The measurement 0.000065 cm written in scientific notation is: 1.5 × 10-8cm

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1 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000


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What is 1 plus 1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111?

1 + 1,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111 = 1,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,112 Unless it is binary, in which case: 1 + 111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 11111 1111 1111 1111 1111 = 1000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000


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G'day,It depends upon your word size and notations use.Irrespective of that, a floating point notation has three parts:Sign Bit | Exponent | MantissaSign Bit is always just one bit.Size of Exponent depends upon a particular selection for a notation. Also, the encoding of Exponent could be in different notation, such as 2's comp, biased, excess, etc.Similarly size of Mantissa depends upon the notation.Here, for your question, I will take 32-bit word for FP and use the following convention.Sign Bit | Exponent | Mantissa1 | 8 bits | 23 bits37 in 2's comp is 100101This could be written as 100101.0000____In normalised form, we start populating the Mantissa using first 1 from the leftMantissa: 1001 0100 0000 0000 0000 000If the radix point were at the extreme left of Mantissa, if would have to be moved 6 places to the right to get the original number. So we encode 6 in excess notation using 8 bits. This forms our Exponent.Exponent: 1000 0110Finally, the number is positive, hence the sign bit will be 0, interpreted as per 2's compSign Bit: 0Put this all together.0 1000 0110 1001 0100 0000 0000 0000 00is 37 in floating point.This is correct to the best of my knowledge. If, however, someone has some correction, please do.Cheers,A


0000?

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