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How is the precision used in measuring the length and width of a rectangle related the precision of the resulting area measurement?
Wiki User
∙ 7y ago
Roughly speaking, the percentage error when you multiply two numbers (measurements) will be similar to the percentage error of each of the individual numbers. Actually, the MAXIMUM percentage error can be approximately as much as the sum of the individual percentage errors, but the EXPECTED percentage error will be less than that.
Wiki User
∙ 7y ago
Wiki User
∙ 7y agoIf the length is L units with a precision of x unitsand the width is W units with a precision of y units
then the precision of the area is taken as L*y + W*x square units.
In fact, the error can be as large as L*y + W*x + x*y but
- if x and y are small compared to L and W, then the x*y term can be ignored, and
- the worst scenario arises only when both errors are in the same direction.
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