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How much greater is the area of a square that has one side equal to 4 feet than a rectangle that measures 3 feet long and 2 feet wide?
Area of square = 4 x 4 = 16 sq ft; area of rectangle = 3 x 2 = 6 sq ft. Area of the square is two-and-two-thirds that of the rectangle.
Area of rectangle perimeter 32 units width 6 units?
The area of a rectangle with a perimeter of 32 units and a width of 6 units the area is 80 square units.Improved Answer:-Area = 6*10 = 60 square unitsPerimeter = 6+6+10+10 = 32 units
The length of a rectangle is 6 times the width The area is 54 square centimeters find the length and width of the rectangle?
6w * w =54w=3L= 6*3=18
What is the area of a square which measures 6 meters on each side?
The area of a square is calculated the same as that of a rectangle: length x width.
If the area of a rectangle is 18 square inches and the length of the rectangle is twice it's width what is the length and width of the rectangle?
A rectangle with one side that is double the length of the other side can be seen as two squares beside each other, that are half the area of the original rectangle, in this case 18 square inches / 2 = 9 square inches. The side of a square is the square root of the area, in this case the square root of 9 square inches, which is 3 inches. Now think about the rectangle again. What we just counted was the side of a square that made up one half of the rectangle you wanted to calculate the area of. So the shorter side of the rectangle is the same as our square, and the longer side is double the length. So the width of the rectangle is 3 inches, and the length is 2 * 3 inches = 6 inches. Or: Area = length x width (A=lw) Area = 18 (in2) Width = w Length = twice width (2w) 18 = (2w)w 18 = 2w2 9 = w2 3 = w The width is 3 in., the length (2w) is 6 in.
