The slope or gradient is the same and would run parallel but the intercept on the y axis would be at -1
y=x+1 there for answer is 2
x = 1 is a graph of a straight line that touches the x-axis at 1 and extends infinitely up and down.
What is the area bounded by the graph of the function f(x)=1-e^-x over the interval [-1, 2]?
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
x + y = 5y = -x + 5The graph is a straight line, with [ slope = -1 ], passing through the point [ y = 5 ] on the y-axis.
y=x+1 there for answer is 2
3
They're exactly the same shape and size, but every point on the graph of the first one is 8 units directly below the corresponding point on the graph of the second one.
(-1,0)
x -3y = 0 -x = -x -3y=-x /-3 = /-3 y=1/3x Then solve y for different values of x, record the data , then graph the x and y position for each value of x. so for if x =1 y = 1/3 so one point on the graph is (1,1/3)
x = 1 is a graph of a straight line that touches the x-axis at 1 and extends infinitely up and down.
1
answer is 1
The slope of the graph of [ y = x + any number ] is 1 .
y 2 1 x 0 1 2
y=-1 No matter what value x has, y is always -1, so the graph is a horizontal line passing through (x,y)=(0,-1).
1