3
I suggest "boring".
The lines are parallel.
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So, if we see the basic equation y=mx+b, we see that m=2, and b=1. If you look closely, this is basic rotation and translation of the original graph. First, I would translate the "mother graph" (y=mx) and then translate one up. Then, we would rotate the graph to the right two units.
A straight line, passing through the point (0,5) with a gradient of -3.
y=x+1 there for answer is 2
No translation will invert a quadratic graph.
To translate the graph y = x to the graph of y = x - 6, shift the graph of y = x down 6 units.
You move the graph upwards by 2 units.
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
I suggest "boring".
y = |x| - 2
The lines are parallel.
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The equation you have given, y + 2 = 7, does not describe a line, it describes the number 5. You would not graph a single number, there is nothing to graph.
So, if we see the basic equation y=mx+b, we see that m=2, and b=1. If you look closely, this is basic rotation and translation of the original graph. First, I would translate the "mother graph" (y=mx) and then translate one up. Then, we would rotate the graph to the right two units.