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You need to know one other thing to answer this question. The acceleration of the braking. The formula is: t=v/a where t is the time, a is the acceleration and v is velocity. For example, in a regular car, to stop from 65 mph (95.3 ft/sec) at a deceleration of 1G (32 feet per second²) would take 2.98 seconds. Incidentally, it would take 142 feet to stop ( formula s=½at² where s is distance).

I assumed you are asking this as it relates to a car. 1G is a very good average braking acceleration for a car.

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15y ago

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Q: How long does it take to stop from 65 mph?
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