Nine years at 8%
Use the "rule of 72"...simply put, using compound interest you take the number 72 and divide it by the interest rate. Thus, at 5% the time to double is 14.4 years. This formula can be used for calculating a "double" for any interest rate using the same mathematical procedure.
72/9 ie 8 years
The same time that it will take for any other amount to double. However, for the actual calculations you need to know the interest rate.
6% of 8,000 = 480 Since interest is not compounded, you just keep getting 480 paid once every year. Mathematically, it takes 8,000/480 = 162/3 years to earn another 8,000. But the final payment isn't paid until the end of the 17th year. Until that moment, you've only collected 7,680. Then, at the end of the 17th year, you get the payment that brings the interest to a total of 8,160. Note that if the interest had only compounded annually ... you leave the interest in the account, and at the end of next year, 6% is paid on the total in the account ... it would double in only 12 years.
14.87% per annum, compounded for 5 years would give back very slightly more than double (2.000014).
Future Value = (Present Value)*(1 + i)^n {i is interest rate per compounding period, and n is the number of compounding periods} Memorize this.So if you want to double, then (Future Value)/(Present Value) = 2, and n = 16.2 = (1 + i)^16 --> 2^(1/16) = 1 + i --> i = 2^(1/16) - 1 = 0.044274 = 4.4274 %
331/3 percent simple interest will double any amount in 3 years.
33 years
It will take 25 years for a 100 to double check if you have a simple interest of 4 percent.
It will take 18 years.
20 YEARS
If the interest rate was eight percent, it would take about 9 years to double your principle.
Use the "rule of 72"...simply put, using compound interest you take the number 72 and divide it by the interest rate. Thus, at 5% the time to double is 14.4 years. This formula can be used for calculating a "double" for any interest rate using the same mathematical procedure.
For continuous compounding: A = Pert Since we need the balance A after t years with a rate of 4.2 % = 0.042 to be 2P, we have A = Pert 2P = Pe(0.042)t 2 = e(0.042)t ln 2 = ln e(0.042)t ln 2 = 0.042t(ln e); (ln e = 1) ln 2 = 0.042t ln2/0.042 = t 16.5 = t Thus after 16 1/2 years the invested money would be doubled.
There's a rule of thumb for "double your money" problems: Time = 70/interest rate, so in this case approx 7 years.
10 years
8 years.