There are 210.
56 The number of triples of 1s on 8 bits
Yes, it is. All you need to do is to ensure that there is no repeating pattern in the digits. You could use random numbers to generate a sequence of 1s and 2s but unfortunately, most of these are actually pseudo-random number generators: they generate sequences which pass the tests for randomness up to a point but eventually fail. You could try linking the decision the hoice of 1s and 2s to tosses of a coin or to radioactive decay which are random.Alternatively, you could try1.21121112111121111121111112... where the length of the string of 1s increases by 1 between the 2s.
1 10 11 12 13 14 15 16 17 18 19 21 31 41 51 61 71 81 91 100 There are 21 "1s" between 1 and 100 including 1 and 100.
Basically, this is the same as finding the number of distinct ways of arranging seven 1s and 3 0s. That is (10!/7!3!) = (10*9*8)/(3*2*1) = 120. There are 120 bit strings of length 10 with exactly three 0s.
There r 16 1s. Including the word one.
5 number 1s so far
4
19 of them.
42
1
1s + 1s + 1 = 2s + 1
6
4 different 1s
One million of them.
An atom can have only one 1s orbital. This orbital can hold up to a maximum of 2 electrons.
i think its 82 not sure