Yes, it is. All you need to do is to ensure that there is no repeating pattern in the digits. You could use random numbers to generate a sequence of 1s and 2s but unfortunately, most of these are actually pseudo-random number generators: they generate sequences which pass the tests for randomness up to a point but eventually fail. You could try linking the decision the hoice of 1s and 2s to tosses of a coin or to radioactive decay which are random.
Alternatively, you could try
1.21121112111121111121111112... where the length of the string of 1s increases by 1 between the 2s.
It is the decimal approximation to the value of the irrational number.
No. Any number which has a finite number of decimal digits is RATIONAL.
A repeating decimal is a rational number. Its value is(the repeating set of digits)/(as many 9s as there are digits above).
NO!!! Because 1.5 can be converted to a quotient ; 1 1/2 or 3/2 . Irrational number are those were the decimal goes to infinity and the decimal digits are in no particulr orderr. 'pi' is the classic axample at 3.141592.....
If the number of digits after the decimal point is finite, then the number will always be RATIONAL.
A decimal expansion means to write out the base 10 digits of a number. Because irrational numbers do not have a closed form, the decimal expansion will always be an approximation. Consider the irrational number pi, which has the following decimal expansion: 3.14159265... Of course there are more digits to pi than that, which is denoted by the "...". It is sadly impossible to list ALL of the digits of an irrational numbers, since if there were a finite number of digits, you could express it as a fraction, which would not be irrational.
It is the decimal approximation to the value of the irrational number.
If it has a finite number of decimal digits, it's rational.
no. an irrational number is that with an infinite non repetitive amount of decimal digits.
The number has a decimal representation that terminates (after 9 digits). If it terminates, the number is rational.
It is not necessarily possible. The value of any irrational number, for example, can be written approximately as a non-terminating, non-repeating decimal but you cannot know all its digits.
A number with a finite number of decimal digits is always rational. (If the number of decimal digits is infinite, the number is rational only if there is a repeating pattern.)
Rational. It is a decimal number that terminates after 15 digits.
No. Any number which has a finite number of decimal digits is RATIONAL.
A repeating decimal is a rational number. Its value is(the repeating set of digits)/(as many 9s as there are digits above).
Irrationals differ from Rationals by definition. If a real number is not a Rational Number then it is Irrational. One way to find out if a number is either Rational or Irrational is to look at its decimal value. If the digits past the decimal point terminate then it is a Rational number. If the digits past the decimal point repeat the same digit forever, of if it repeats a sequence of digits over and over, then it is a Rational Number. If the digits past the decimal point do not repeat in any pattern, and do not stop, then it is an Irrational number. Another way to find out if a number is Rational or Irrational is if it can be exactly described by a fraction (ratio). If it is the same as some fraction, then it is a Rational Number. Irrationals cannot be exactly described as a fraction.
NO!!! Because 1.5 can be converted to a quotient ; 1 1/2 or 3/2 . Irrational number are those were the decimal goes to infinity and the decimal digits are in no particulr orderr. 'pi' is the classic axample at 3.141592.....