160 games will give 3 winning numbers everytime.
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I have no idea where that answewr - to a question that wasn't even asked - came from. The correct answer is 45C3 = 45*44*43/(3*2*1) = 14,190.
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There are just 5,005.There are 10C6 = 210 combinations with 6 different numbers.There are 10C5 = 252 combinations with 5 different numbers. One of these needs to be duplicated and the one to be duplicated can be chosen in 5 ways so there are 1260 of these.There are 10C4 = 210 combinations with 4 different numbers. Either one of them appears three times or two are doubled. That can be done in 10 ways so there are 2,100 of these.There are 10C3 = 120 combinations with 3 different numbers. Either one of them appears 4 times, or one twice and another three times, or all three appear twice. That can be done in 10 ways so there are 1,200 of these.There are 10C2 = 45 combinations with 2 different numbers. Either one of them appears 5 times, or one twice and another four times, or both three times. That can be done in 5 ways so there are 225 of these.There are 10C1 = 10 combinations with just 1 number repeated six times.Add these together.
-.45 is rational. Rational numbers are numbers that can be written as a fraction. Irrational numbers cannot be expressed as a fraction.
Once you put the numbers in order, the median is the middle number or the average of the 2 middle numbers. 13, 19, 39, 44, 45, 58, 68. 44 is the number in the middle, so 44 is the median.
What you have to do is you add up all the numbers then you divide by the number of numbers. ex. Say you have the numbers 45,56,39 and 35 you add them all up 45+56+39+35=175 then you divide 175/4(because there is 4 numbers)=43.75
You can use the formula for the sum of an arithmetic series. Sn = (n/2)[2a + (n - 1)d].....n is the number of terms, a is the first term and d the common difference between terms. In this question, n = 45, a = 1 (as 1 is the first odd number) and d = 2 (the difference between consecutive odd numbers). Then, S(45) = (45/2)[2 + 44x2] = (45/2) x 90 = 2025.