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You can use the formula for the sum of an arithmetic series.
Sn = (n/2)[2a + (n - 1)d].....n is the number of terms, a is the first term and d the common difference between terms.
In this question, n = 45, a = 1 (as 1 is the first odd number) and d = 2 (the difference between consecutive odd numbers).
Then, S(45) = (45/2)[2 + 44x2] = (45/2) x 90 = 2025.
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What is the sum of the first 700 consecutive odd numbers?
490,000
What is the sum of the first 40 consecutive odd numbers?
The answer is 1600. All you have to do is times the number given into itself. Example first 50 odd numbers would be 50x 50= 2500.
What is the sum of the first 800 consecutive odd numbers?
640000. First odd number is 1, 800th odd number is 1599, giving their sum: sum = number_of_numbers x (first_number + last_number) ÷ 2 = 800 x (1 + 1599) ÷ 2 = 640000
The sum of three consecutive even integers that give you 151 and tha sum of three consecutive odd integers that give you 150?
There are no such answers. The sum of even numbers is even. The sum of odd numbers could be even, but the sum of three consecutive odd numbers is always odd. One could swap the questions to get potentially answerable questions: Sum of 3 consecutive EVEN integers = 150 48 + 50 + 52 = 150 unfortunately, we can already see that if we were to make these odd integers (add 1 to each), we would get 153, not 151. Sum of 3 consecutive ODD integers = 151 49 + 51 + 53 = 153 47 + 49 + 51 = 147 We can see that, whenever we slide our three consecutive integers up one, we raise the value of the sum up 3, and if we jump from odd to odd, or even to even, we raise each integer by 2, so we raise the sum by 6.
The sum of the squares of two consecutive odd integers is 34 what are the numbers?
3 and 5
