To calculate the number of combinations of 5 numbers possible from 1 to 49, we use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 49 (total numbers) and r = 5 (numbers chosen). Plugging these values into the formula, we get 49C5 = 49! / (5!(49-5)!) = 1,906,884 combinations.
7*7 = 49 numbers.7*7 = 49 numbers.7*7 = 49 numbers.7*7 = 49 numbers.
The next two square numbers after 30 are 36 and 49
The greatest common factor that is possible for two numbers between 40 and 50 would be 10 if both 40 and 50 are allowed, since 50 - 40 = 10. If only the numbers from 41 to 49 are allowed, the difference is 8, so 8 would be the largest possible common factor, but neither 41 nor 49 are divisible by 8, so that situation does not exist. However, 42 and 49 are both divisible by 7, which is their greatest common factor.
Two. 36, and 49 are perfect squares.
The numbers are 49 and 16
There are infinitely many possible answers. Two such are: 1.5 + 47.5 and 49049/1001
There are 15 prime numbers between 1 and 49
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
Between the two numbers there are 49.
Three: 1 7 49.
Three: 1 7 49.
7*7 = 49 numbers.7*7 = 49 numbers.7*7 = 49 numbers.7*7 = 49 numbers.
100
There are 48/2 + 1 = 25 odd numbers in 1 to 49, inclusive.
Infinitely many.
49 of them.
nCr = n!/((n-r)!r!) → 49C8 = 49!/((49-8)!8!) = 49!/(41!8!) = 450,978,066 combinations.