It can have 120 combinations . . .
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6 over 3, or 6 combination 3, is calculated as (6 x 5 x 4) / (1 x 2 x 3).
2.3 recurring
4*3*2*1 = 24 ways.4*3*2*1 = 24 ways.4*3*2*1 = 24 ways.4*3*2*1 = 24 ways.
3! = 1 x 2 x 3 = 6. The same for any three different digits - you have 6 possible combinations. * * * * * NO! That is the number of permutations! In a combination the order of the numbers does not matter, so there is only one combination 123. And that is the same as 132, or 312 or ...
4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6 4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6 4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6 4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6