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To calculate the number of combinations of four numbers from a set of 32 numbers, you can use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 32 (total numbers) and r = 4 (numbers chosen). Plugging these values into the formula, you get 32C4 = 32! / (4!(32-4)!) = 32! / (4!28!). After calculating this expression, you will find that there are 35,960 possible combinations of four numbers from a set of 32 numbers.
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How many combinations of 3 numbers are there in 32 numbers what are these combinations?
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
How many combinations are there with 5 numbers?
5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.
How many combinations of 6 numbers are there in 33?
There are 33C6 = 33*32*31*30*29*28/(6*5*4*3*2*1) = 1,107,568 combinations.
How many combinations does 5 checkboxes give?
Assuming there are 5 check boxes and the respondent may check any number of them, the answer is 25 = 32 combinations.
What two numbers multiply together to equal -32 and add together to equal 2?
-30
How many combinations of 3 numbers are there in 32 numbers what are these combinations?
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
What are the four numbers that add up to 32?
There are many combinations of four numbers that can add up to 32. For example, one possible set of numbers is 8, 8, 8, and 8. Another combination could be 5, 10, 7, and 10. The specific numbers can vary based on the constraints or requirements given.
How many combinations are there for 4 numbers from 9 to 32?
there are altogether 24 numbers between 9 and 32. by using nCr, 24C4 = 10626
How many number combinations for the numbers 1 through four?
1 and 11 and 21 and 31 and 42 and 12 and 22 and 32 and 43 and 13 and 23 and 33 and 44 and 14 and 24 and 34 and 416 combinations
How many 4 number combinations are there with numbers 1 through 35 without repeating any numbers?
There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
How many combinations are there with 5 numbers?
5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.
How many combinations of 6 numbers are there in 33?
There are 33C6 = 33*32*31*30*29*28/(6*5*4*3*2*1) = 1,107,568 combinations.
How many combinations of 5 numbers are there in 32 numbers?
The answer is 32!/(27! * 5!) where n! represents 1*2*3*... *n So the answer is 32*31*30*29*28/(5*4*3*2*1) = 201 376
How many different 5 number combinations can be made from the numbers 1 - 32?
If repetitions are allows, 325. If no repetitions are allows, then it is 32 x 31 x 30 x 29 x 28.
How many possible combinations can you get between the range 1 to 32?
It depends on how many numbers make one combination.Here are the possibilities for combinations of several different sizes:Numbers in the combinationPossible combinations1 . . . . . 322 . . . . . 4963 . . . . . 4,9604 . . . . . 35,9605 . . . . . 194,4326 . . . . . 906,1927 . . . . . 3,365,8568 . . . . . 10,518,300
How many winning combinations in 5 NBA games?
32 of them.
If you wanted to know how many 5 digit combinations you could make using only 2 digits how would you solve this?
Simple enough to solve. The answer is a power of two. Assuming you have two possible digits, say for example, 3 and 4, then you simply have to multiply it by how many numbers you want to get the total number of combinations. Each number can be 3 or 4 in this case, and you have 5 numbers. That's two to the fifth. Five combinations of any two numbers. 2x2x2x2x2. The answer is 32 combinations.
