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To calculate the number of combinations of four numbers from a set of 32 numbers, you can use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 32 (total numbers) and r = 4 (numbers chosen). Plugging these values into the formula, you get 32C4 = 32! / (4!(32-4)!) = 32! / (4!28!). After calculating this expression, you will find that there are 35,960 possible combinations of four numbers from a set of 32 numbers.
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How many combinations of 3 numbers are there in 32 numbers what are these combinations?
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
How many combinations are there with 5 numbers?
5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.
How many combinations of 6 numbers are there in 33?
There are 33C6 = 33*32*31*30*29*28/(6*5*4*3*2*1) = 1,107,568 combinations.
How many combinations does 5 checkboxes give?
Assuming there are 5 check boxes and the respondent may check any number of them, the answer is 25 = 32 combinations.
What two numbers multiply together to equal -32 and add together to equal 2?
-30
