answersLogoWhite

0


Best Answer

To calculate the number of combinations of four numbers from a set of 32 numbers, you can use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 32 (total numbers) and r = 4 (numbers chosen). Plugging these values into the formula, you get 32C4 = 32! / (4!(32-4)!) = 32! / (4!28!). After calculating this expression, you will find that there are 35,960 possible combinations of four numbers from a set of 32 numbers.

User Avatar

ProfBot

19h ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

18y ago

32x31x30x29, or 863040. Considering that repeating numbers are not allowed, if they are it's 32x32x32x32 or 1,048,576...you'll win slightly less than what you spend if you're looking at the Pick 4! Lotteries, like casinos have the numbers on their side.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many combinations of four numbers are there in 32 numbers?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many combinations of 3 numbers are there in 32 numbers what are these combinations?

There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.


How many combinations are there for 4 numbers from 9 to 32?

there are altogether 24 numbers between 9 and 32. by using nCr, 24C4 = 10626


How many combinations are there with 5 numbers?

5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.


How many number combinations for the numbers 1 through four?

1 and 11 and 21 and 31 and 42 and 12 and 22 and 32 and 43 and 13 and 23 and 33 and 44 and 14 and 24 and 34 and 416 combinations


How many 4 number combinations are there with numbers 1 through 35 without repeating any numbers?

There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.


How many combinations of 6 numbers are there in 33?

There are 33C6 = 33*32*31*30*29*28/(6*5*4*3*2*1) = 1,107,568 combinations.


How many combinations of 5 numbers are there in 32 numbers?

The answer is 32!/(27! * 5!) where n! represents 1*2*3*... *n So the answer is 32*31*30*29*28/(5*4*3*2*1) = 201 376


How many different 5 number combinations can be made from the numbers 1 - 32?

If repetitions are allows, 325. If no repetitions are allows, then it is 32 x 31 x 30 x 29 x 28.


How many combinations of 4 numbers can be made of 36 numbers if you can not repeat the numbers?

( 36! )/( 32! ) ( 4! ) = (36 x 35 x 34 x 33)/(4 x 3 x 2) = 58,905


How many possible combinations can you get between the range 1 to 32?

It depends on how many numbers make one combination.Here are the possibilities for combinations of several different sizes:Numbers in the combinationPossible combinations1 . . . . . 322 . . . . . 4963 . . . . . 4,9604 . . . . . 35,9605 . . . . . 194,4326 . . . . . 906,1927 . . . . . 3,365,8568 . . . . . 10,518,300


If you wanted to know how many 5 digit combinations you could make using only 2 digits how would you solve this?

Simple enough to solve. The answer is a power of two. Assuming you have two possible digits, say for example, 3 and 4, then you simply have to multiply it by how many numbers you want to get the total number of combinations. Each number can be 3 or 4 in this case, and you have 5 numbers. That's two to the fifth. Five combinations of any two numbers. 2x2x2x2x2. The answer is 32 combinations.


How many winning combinations in 5 NBA games?

32 of them.