To determine the number of cuboids that can be made with a volume of 24 cubic centimeters, we need to find all the possible combinations of length, width, and height that multiply to give a volume of 24 cm³. The factors of 24 are 1, 2, 3, 4, 6, 8, 12, and 24. Each of these factors can be paired with another factor to form a unique cuboid, resulting in a total of 12 possible cuboids with a volume of 24 cm³.
Infinitely many.
Select any number A such that 0 < A ≤ cuberoot(24) = 2.8845 approx.
Then let S = 24/A
Next, let B be a number such that A ≤ B ≤ sqrt(S)
and let C = 24/(A*B)
Then it can be shown that A ≤ B ≤ C
and a cuboid with sides of length A, B and C will ave a volume of A*B*C = 24 cm3.
There are infinitely many possible values for A so that there are infinitely many possible cuboids.
Anything greater than 24 cm. P = 2*L + 2*W, since the length is fixed at 24cm we have: 2*(24cm) +2*W > 96cm 2W > 96 - 48cm 2W > 48cm, or Width > 24cm. So any width greater than 24cm will make the perimeter >96cm. Obviously a width of 24cm wouldn't work since a polygon with all four sides equal would be a square and not a rectangle.
Oh, dude, like, when you see p cubed in an expression, it means you're multiplying p by itself three times. So, it's like p * p * p. It's just a fancy math way of saying "Hey, let's make p hang out with itself a couple more times."
pi*radius2*height = volume Make the height the subject of the above formula:- height = volume/pi*radius2
The new dimensions can be any length and any width that multiply to make 864. If you want to keep the same aspect ratio (shape), then the new dimensions are 24cm by 36 cm .
Squared. When you find surface area, you are only finding the area of the shapes that make up the three-denominational shape.
4
That would obviously depend on how big you want your cuboids.
cubed units
25
Fill a market beaker to a specific measured volume. (Eg. 50cm cubed, make sure you have not filled the beaker with water). Now place the object in the beaker with water. The water level should rise (Eg. from 50cm cubed to 60cm cubed). The difference in the original volume and the final volume is the volume of the object. That is the water displacement method.
Twenty
Four.
You can't associate volume and length. I'll make an assumption that you either meant millimetres cubed or millilitres. There are 100,000 millimetres cubed in a decilitre. There are 100 millilitres in a decilitre.
Density = m/v right? Find the density of ice (easy google search), you have the volume, then solve for mass. Remember to convert ft cubed into meters cubed and make sure other units are the same.
You could try 14!
There are 12 different cuboids which are possible.
Anything greater than 24 cm. P = 2*L + 2*W, since the length is fixed at 24cm we have: 2*(24cm) +2*W > 96cm 2W > 96 - 48cm 2W > 48cm, or Width > 24cm. So any width greater than 24cm will make the perimeter >96cm. Obviously a width of 24cm wouldn't work since a polygon with all four sides equal would be a square and not a rectangle.