Best Answer

Anything greater than 24 cm. P = 2*L + 2*W, since the length is fixed at 24cm we have: 2*(24cm) +2*W > 96cm 2W > 96 - 48cm 2W > 48cm, or Width > 24cm. So any width greater than 24cm will make the perimeter >96cm. Obviously a width of 24cm wouldn't work since a polygon with all four sides equal would be a square and not a rectangle.

User Avatar

Wiki User

โˆ™ 2008-04-10 11:40:23
This answer is:
User Avatar
Study guides


20 cards

A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

See all cards
1759 Reviews

Add your answer:

Earn +20 pts
Q: The length of a rectangle is fixed at 24 cm what widths will make the perimeter greater than 96 cm?
Write your answer...
Still have questions?
magnify glass
Continue Learning about Algebra

The length of a rectangle is 2in more than twice its width and the perimeter of the rectangle is 16in find the width of the rectangle?

Using algebra to solve this geometric problem, call the width w inches long.Therefore the length is 2w+2 inches (i.e. "2in more than twice its width").There are two widths and two lengths in the perimeter so now add them up. w+w+2w+2+2w+2=6w+4 The perimeter is equal to 16 inches, so 6w+4=16 6w=12 w=2 inches

How many widths go into length?


What are the possible perimeter lengths and widths of that the 30 feet rectangular shaped garden?

Since the question asks about the perimeter, lengths and widths, it is not clear what the 30 feet measure, which is given in the question, refers to! Without that information, it is impossible to answer the question.

A certain rectangle has a width that is half the difference of the length and 6 cm If the Perimeter of the rectangle is 87 cm what is the length and width of the rectangle?

Algebra works great here. Let's use three variables: P for perimeter, L for length and W for width. Then we can rewrite the above in terms of math:W = (1/2)(L - 6)

On graph paper letting 1 foot represent each square draw a rectangle 1'L x 10'W x 22'Perimeter x 10'squared Area?

The question is perhaps a bit confusing, because normally when we use the terms length and width in describing rectangles, the length refers to the longer dimension, and the width to the shorter. Because the question is worded so as to depart from that convention, it is reasonable to revert to the graph paper convention of making widths horizontal (along rows) and lengths vertical (along columns), even if the length is shorter than the width. So that means the answer is to draw along the perimeter of a group of 10 consecutive boxes in a single row on the graph paper.

Related questions

How do i find the perimeter of a rectangle if you know its length and its width?

Add up (two lengths) plus (two widths) and you have the perimeter.

The length of a rectangle is fixed at 24 cm what widths will mame the perimeter greater than 100cm?

P (perimeter of a rectangle) = 2*l+2*w 2*24+2*w > 100 2*w > 52 w > 26 Any width greater than 26cm will cause the perimeter to be greater than 100cm.

What is the length of the sides of a rectangle that has a perimeter of .875?

You can't tell the dimensions from the perimeter. There are an infinite number of different rectangles, all with different lengths and widths, that all have the same perimeter.

The perimeter of a rectangle is 130m. The length of the rectangle is 25m more than the width. What are the lengths and widths of the rectangle?

x=width x+25=length 4x+50=130 4x=80 x=20 width is 20 length is 45

How do you know that the perimeter of a rectangle is directly proportional to its length?

The perimeter of a rectangle is given by the formula P = 2(l + w). It is clear that as the length, l, increases, the perimeter, P, increases, as well. We say, therefore, that P is directly proportional to l. If l is the length and b is width of a rectangle then, the perimeter P of the rectangle is 2(l + b) units. P = 2(l + b) P = 2l + 2b If have b as a constant then, 2b will be a constant. Now l is the varying quantity. Say 2b = K P = 2l +K Perimeter changes if the length of the rectangle changes. In particular, if the length increases the perimeter of the rectangle increases. Similarly, if the length decreases the perimeter also decreases. So, the perimeter is directly proportional to the length of the rectangle. Source: In the most simplest explanation, the sum of both lengths, and both widths of the rectangle, IS the perimeter. So obviously the perimeter is directly proportionate to its length (and its width).

What is width of rectangle with length 40 meters and perimeter 120 meters?

To find the perimeter of the rectangle you add up all the sides. There are two lengths and widths for every rectangle, so you know the length is 40 meters x 2 = 80 meters. Perimeter is the total length of all the sides so you just minus 120 from the two lengths which is 80. So the width is 40, divide 2 (2 widths) = 20 meters. Width = 20 meters OR if they're asking for widthS then it'll be 40 meters, but they're not.

How do you write the perimeter of a rectangle in sentence form?

The perimeter of a rectangle, like the perimeter of any closed two-dimensional figure, is the distance around it. The perimeter of the rectangle is the sum of two lengths plus two widths.

What is the width and length of a rectangle if the perimeter is 50 and the length is 5 cm more than the width?

Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm

Can a rectangle have a congruent opposite sides?

Yes, it normally has opposite congruent lengths and opposite congruent widths. The length of a rectangle is normally greater than its width.

How many widths to a length?

There will be Length/Width widths in 1 length. This will normally be a number that is greater than 1.

How do you find the widths of a rectangle with the lengths?

You can't find the widths of a rectangle with the lengths because the widths can be anything lower than the lengths. Like if your rectangle had a length of 7 the width can be 6, 5, 4, 3, 2, and so on.

A rectangle has a perimeter of 10 ft Write the area A of the rectangle as a function of the length of one side x of the rectangle?

This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.

People also asked