There can be 14 lines in a seven side shape
* * * * *
That is the total number of diagonals from ALL vertices. Not what the question asked, though.
From one vertex, there can be 4. One to every other vertex except for itself and one each on either side.
51º per interior angle
seventy seven quintillion, seven hundred seventy seven quadrillion, seven hundred seventy seven trillion, seven hundred seventy seven billion, sevenhundred seventy seven million, seven hundred seventy seven thousand, seven hundred seventy seven. :-)
seven sixteenths 7/16
The sum of six and seven is expressed as six plus seven. The full equation would be six plus seven equals thirteen.
They are not generally called seven cubes.
A shape with ten sides and seven vertex is impossible. There must always be the same amount of sides as vertex in a shape.
If it was an heptagon it would have 14 diagonals
If you are merely drawing from one vertex to all the others, the number of triangles in any n-sided figure is equal to n-2. In this case, a heptagon has seven sides, and thus (7 - 2) = 5 triangles can be drawn.
A shape with ten sides and seven vertex is impossible. There must always be the same amount of sides as vertex in a shape.
There are 14 diagonals in a septagon. Another name for a septagon is heptagon. This is a seven-sided polygon. To figure the numbers of diagonals, you can use the formula 1/2 x [n x (n-3)], where n is the number of sides.
A polygon with seven sides is called a septagon.
A polygon with seven sides is a heptagon.
A seven-sided polygon is called a heptagon.
The name for the polygon with seven sides is a heptagon.
On the internet I found that a polygon with seven sides is called a heptagon.
A seven-sided polygon is a heptagon.
There are 7*(7-3)/2 = 7*4/2 = 14 diagonals.