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A hexagon has 9 diagonals.
Each vertex of a n-sided polygon can be connected to n - 3 others with diagonals.
Thus n(n - 3) possible diagonals. However, when Vertex A is connected to vertex C, vertex C is also connected to vertex A, thus each diagonal is counted twice.
Thus: number_of_diagonals = n(n - 3)/2
= 6(6-3)/2
= 6x3/2
= 9
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∙ 10y ago
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∙ 15y ago9
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