About 175
The question "Something divided by something equals 65" can be represented as a mathematical equation: x / y = 65. To solve for x or y, we need more information or context. If x is known, we can find y by dividing x by 65. If y is known, we can find x by multiplying y by 65. Without specific values for x or y, the equation remains unsolvable.
Time = Distance/Speed = 619/65 = 9.52 hours - assuming that an average speed of 65 mph can be maintained for that length of time, allowing for refuelling stops, comfort stops etc.
Factorial 65 = 8247650592082470666723170306785496252186258551345437492922123134388955774976000000000000000
-65
65
65. The number of diagonals in a polygon with n sides is given by: diagonals = n(n - 3) / 2 So for a triskaidecagon which has 13 sides n = 13 and: number_of_diagonals = 13(13 - 3) /2 = 13 x 10 / 2 = 65
I'm pretty sure it's 65
Suppose the polygon has V vertices.Then sum of interior angles is (V - 2)*180 degrees = 1980 degrees => V - 2 = 1980/180 = 11 => V = 13 A polygon with V vertices has V*(V-3)/2 = 13*10/2 = 65 diagonals.
65
If you mean a triskaidecagon then it has 65 diagonals
A triangle has no diagonals
The formula which tells you the number of diagonals possible in a regular polygon is:the number of points (or sides), which we will call 'n', multiply by (n-3). Then divide the answer by 2.This will give you the number of diagonals.Formula: n X (n-3)/2ExamplesA square has four sides.4 X (4-3) = 2Divide 2 by 2 = 2So a square, a 4-sided polygon, has two diagonals.A pentagon has five sides5 X (5-3) = 10Divide 10 by 2 = 5So a 5-sided polygon has 5 diagonalsUsing the same formula we can calculate the number of diagonals of any regular polygon.e.g. 13-sides13 X (13-3) = 130Divide 130 by 2 = 65So a 13-sided polygon has 65 diagonals!If a polygon is irregular, meaning that its sides are of different lengths, and if all the points of the polygon are pointing outwards, the same formula holds true.But if the polygon is so irregular that some of its angles point inwards, there is no way of computing the number of diagonals because, in some irregular polygons, some potential diagonals may be impossible to reach from one point to the other without going outside the boundary of the polygon.
They have: 0.5*(132-(3*13)) = 65 diagonals
It has 65 sides.
formula n/2(n-3) so, 13/2(13-3) Diagonal is 65
65. The equation to figure the number of diagonal lines for any polygon is n(n-3)/2. n= number of vertices