36
8. A way to work this out is figure out how many possible digits can go in each place value position (units, tens, hundreds) and multiply these together. Since there are 2 possible digits that can go in each position and there are three positions, you would go: 2 x 2 x 2 = 8 Want a list? 222 225 252 255 555 552 525 522
If the number with the digits reversed can have a leading 0 so that it is a 1-digit number, then 16. Otherwise 13.
120 There are 6 digits in total. The numbers with 3 digits, with all digits distinct from each other, are the permutations of the 6 digits taken 3 at a time, and therefore there are 6*5*4 = 120 of them.
ten
1+2 2/$)$+/
151.208 to 2 significant figures is 150.
7
10 digits
2 digits are in 30
There are 2 digits in 30. They are 3 and 0.
5 significant digits.
Depends on what they are, and how many total digits.
No, because the last 2 digits are not divisible by 4. 50 is not divisible by 4 so No!
5.8x10=58. There are exactly 2 digits in 58.
There are 75 2's in 150
There are many symbols that have no digits. 2 of these symbols might be a dove and a tree for example.