36
Since there are only five different digits, a 6-digit number can only be generated if a digit can be repeated. If digits can be repeated, the smallest 6-digit number is 111111.
This is really a question about permuations with repeated elements. The formula for that is n!/a! b!... where a, b,.. are repeated So we have 6 elelments with each repeated 2 times. so the number is. 6!/2!2!2! This is 6x5x4x3x2x1/ 23 so we can cancel out the 4 and the 2. 6x5x3=90 So 90 different numbers.
There are 26 different letters that can be chosen for each letter. There are 10 different numbers that can be chosen for each number. Since each of the numbers/digits that can be chosen for each of the six "spots" are independent events, we can multiply these combinations using the multiplicative rule of probability.combinations = (# of different digits) * (# of different digits) * (# of different digits) * (# of different letters) * (# of different letters) * (# of different letters) = 10 * 10 * 10 * 26 * 26 * 26 = 103 * 263 = 1000 * 17576 = 17,576,000 different combinations.
To form a four-digit number without repeating any digits from 56789, we need to choose 4 different digits out of the 5 available. This can be done in 5 choose 4 ways, which is equal to 5! / (4! * (5-4)!) = 5 ways. Therefore, there are 5 four-digit numbers that can be formed out of 56789 without repeating any digits.
648
The answer will depend on how many digits you have at your disposal. Working with the 10 digits, and barring leading zeros, there are 8,877,690 numbers.
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
98,764
Infinite. If numbers can be repeated, the list could go on nonstop.
763920
It is possible to create a 3-digit number, without repeated digits so the probability is 1.
If the digits can be repeated, then there are (5 x 5 x 5 x 5) = 625 different four-digit numbers.If the digits can't be repeated, then there are (5 x 4 x 3 x 2) = 120 different four-digit numbers.
9!/(5! x 4!) = (9 x 8 x 7 x 6) / (4 x 3 x 2) =126 if all digits have to be different. If repeated digits are allowed then it is 95 ie 59049.
757
If you allow digits to be repeated (for example, 222 or 992), then there are 9 x 9 x 9 = 729 combinations. If you do not allow digits to be repeated, then there are 9 x 8 x 7 = 504 combinations.
With repeated digits, 43 = 64 Without repeated digits, 4*3*2 = 24
500