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How many four digit numbers can be formed using the digits 0123456789 if the repetitions of digits are allowed?
If you don't mind beginning the 4-digit number with one or more zeros, then
there are 10 choices for each digit, and the total number of possibilities is:
(10 x 10 x 10 x 10) = 10,000 .
If the 4-digit number can't begin with a zero, then there are only 9 choices for
the first digit, but 10 choices for each of the others, and the total number of
possibilities is:
(9 x 10 x 10 x 10) = 9,000 .
What else can I help you with?
How many 4 digit numbers can be formed using the digits 0 1 2 3 4 5 6 7 8 9 if repetitions of digits are allowed?
10,000
How many 6 digit numbers can be formed using the digits 0 1 2 3 4 5 6 7 8 9 if repetitions of digits are allowed?
There are 10 numbers in all including 0. The first space can be filled in 9 ways (as we have to exclude 0). The second through sixth spaces can be filled in 10 ways as 0 can be included. Totally, 9 x 10 x 10 x 10 x 10 x 10 or 9 x 10^5 digits can be formed if repetition is allowed.
Where are the digits 0123456789 in pi?
The digits 0123456789, representing the numbers from 0 to 9, can be found in the decimal representation of pi. However, pi is an irrational number, meaning it has an infinite number of non-repeating digits. Therefore, while these digits do appear in pi, they occur in a seemingly random and unpredictable manner throughout its decimal expansion. As of now, no pattern has been discovered in the distribution of these digits within pi.
How many 3 digit numbers can be formed using the digits 2 3 5 6 7 9 if repetition of digits is not allowed?
120 There are 6 digits in total. The numbers with 3 digits, with all digits distinct from each other, are the permutations of the 6 digits taken 3 at a time, and therefore there are 6*5*4 = 120 of them.
How many digits are there in the numbers 100-425?
525
How many four digit numbers can be formed from the digits 1 and 2 if repetitions are allowed?
pizza
How many digits numbers each less than 500 can be formed from the digits 13467 if repetitions is allowed?
There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.
How many 3 digit number can be made using the digits 2 4 7 9?
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
How many six digit numbers can be formed using the digits 0123456789 Example equals 123456 or 098765?
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
How many 4 digit numbers can be formed using the digits 0 1 2 3 4 5 6 if repetitions of digits are allowed?
2,401
How many 6 digit numbers can be formed with 1 to 45 digits?
Assuming all 45 digits are different (which they will not be if they are ordinary integers), then 456, if repetitions are allowed. That is 8303765625. If repetitions are not allowed then the number falls to 45*44*43*42*41*40 = 5864443200
How many 4 digit numbers can be formed using the digits 0 1 2 3 4 5 6 7 8 9 if repetitions of digits are allowed?
10,000
What is the term for any one of the ten symbols 0123456789 used to write numbers?
They are called decimal digits.
How many 3 digit numbers divisible by 9 can be formed from the digits 0123456789?
There are 76 such numbers. Eight more if you allow numbers to start with 0.
How many 5-digit numbers can be formed using the digits 0 1 2 3 4 5 if repetitions are allowed exactly divided by 4?
5^4
How many 3 digit numbers can be formed from the digits 357 with any digit repeated?
27 three digit numbers from the digits 3, 5, 7 including repetitions.
How many 3-digit codes using digits 0 through 9 are possible if repetitions are allowed?
10,000
