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There are 28C6 = (28*27*26*25*24*23)/(6*5*4*3*2*1) = 376,740 sets.

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Q: How many groups of 6 numbers can you get from the numbers 1 to 28?
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Related questions

Can anyone give you the set of numbers in groups of 6 with the numbers being from 1 - 28?

Yes, they can.


How many groups of 2 are there in 8?

There are 4 groups of 2 in 8 (2X4=8, 8/2=4)There are 28 pairs in all the numbers between 1 and 8 (1&2,1&3, etc.)


How many groups of 6 different numbers out of 8?

The answer is 8C6 = 8!/[6!*(8-6)!] where n! = 1*2*3*...*n So, the answer is 28.


How many numbers go into 28?

1, 2, 4, 7, 14, 28.


How many numbers divide into 28 with no remainder?

1, 2, 4, 7, 14, and 28 are the numbers that match this description. Therefore, six numbers divide into it evenly.


How many groups of 4 numbers are in 6 numbers?

If the six numbers are all different, then the answer is 6C4 = 6*5/(2*1) = 15


What numbers are multiplied to get the number 28?

There are infinitely many possible answers: 1*2*14 = 28 or 5*20*0.28 = 28


What is 56 split into equal groups?

56 will split into the following groups... 56 groups of 1 28 groups of 2 14 groups of 4 7 groups of 8 8 groups of 7 4 groups of 14 2 groups of 28 and 1 group of 56


How many unique sets of 6 can you get from 1 to 28?

It looks like you are asking how many combinations of 6 numbers are there in the 28 numbers 1 through 28. This is known as the number of combinations of 28 things taken 6 at a time. The answer is 28!/(6!22!) (n! means n factorial, which is the product of all the integers from 1 to n). I get 376,740 if I haven't made an error in arithmetic.


What are two LCM numbers of 28?

Two numbers that have an LCM of 28 are 14 and 28.


How many combinations of 2 can you get in 8 numbers?

There are 8*7/(2*1) = 28 combinations.


What numbers can divided into 28 evenly?

1, 2, 4, 7, 14, and 28 are the numbers you seek.