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A chemist has one solution which is 50 percent acid and a second solution which is 25 percent acid how much of each should be mixed to make a 10 liters of a 40 percent acid solution?
6 litres of 50% + 4 litres of 25%
How many liters of water must be added to 7 liters of a 20 percent acid solution to obtain a 10 percent acid solution?
7 liters of a 20% acid solution consists of 1.4 liters of acid (20% of the total volume) mixed with 5.6 liters of water (80% of the total volume). The amount of acid isn't going to change in the new solution. You are just going to add enough water to make it a 10% solution instead of a 20% solution. So it will be more dilute. That means that 1.4 liters of acid will represent 1/10 of the volume of the new solution. So the total volume of the new solution will be 10 x 1.4 or 14 liters. The amount of water in the new solution will be 14 - 1.4 = 12.6 liters. That is a difference of 12.6 - 5.6 = 7 liters from the amount of water you started with. So you need to add 7 liters of water to the original 20% solution to make it a 10% solution. This makes sense because if you double the amount of the mixture from 7 liters to 14 liters and the amount of acid is unchanged, the solution will be half as strong.
How many liters of water must be added to 30 liters of 20 percent ALCOHOL solution to dilute it to a15 percent solution?
You have 6 litres of alcohol in 24 litres of water You need to add x litres to make 6 equal to 15% of 30 + x. 6 is 15% of 40, so x = 10
How can we convert 25 percent of ammonia solution to 10 M?
25% ammonia solution means 25g Ammonia in 100ml of water. To convert it into moles i.e for 1000ml solvent, 25x100=250 which means 250g of ammonia is present in 1000ml of water to make a 25%solution. To convert it into molar solution we will divide 250 by the molecular mass of ammonia i.e 17. 250/17= 14.71M This means that 25% ammonia solution contains 14.71 moles of ammonia. Now we will use the formula M1V1=M2V2 Let's say we want to make 10 molar solution in 500ml water. Then, M1=14.71 V1=? M2=10 V2=500 Putting values in the above equation: 14.71xV1 = 10x500 V1 = 10x500 / 14.71 = 340ml We will take 340ml of the 25% ammonia solution and make the volume up to 500ml with water. This will be our 10 molar solution of Ammonia.
A chemist wants to make a 10 solution of fertilizer. how much water and how much of a 30 solution should the chemist mix to get 30 L of a 10 solution?
30 liters of a 10 % solution of fertilizer has .1(30) = 3 liters of fertilizer 1 liter of 30% solution has .3 liter of fertilizer 10 liters of 30% solution has 3 liters of fertilizer so, the chemist needs 10 liters of the 30% solution and 20 liters of water to make 30 liters of a 10% solution.
A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid How much of the second 30 percent solution is needed to make a 400 L solution that is 62 percent acid?
144liters
A chemist is making 200 L of a solution that is 62 percent acid He is mixing an 80 percent acid solution with a 30 percent acid solution How much of the 80 percent acid solution will he use?
The chemist will use 100 liters of the 80% acid solution and 100 liters of the 30% acid solution to make a 200-liter solution that is 62% acid. The amount of acid in the 80% solution will be 0.8 * 100 = 80 liters, and in the 30% solution, it will be 0.3 * 100 = 30 liters.
A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid How much of the first 80 percent solution is needed to make a 400 L solution that is 62 percent acid?
To create a 400 L solution that is 62% acid, you would need 200 L of the 80% acid solution and 200 L of the 30% acid solution. This would result in a final solution with the desired concentration.
A chemist has one solution which is 50 percent acid and a second solution which is 25 percent acid how much of each should be mixed to make a 10 liters of a 40 percent acid solution?
6 litres of 50% + 4 litres of 25%
How many liters of 93 percent acid solution are needed to make a 9 percent solution with 50 liters of water?
4.84
Jorge has four liters of 30 percent acid solution how much water should he add to make 25 percent acid solution'?
Jorge needs to add 2 liters of water to the 30% acid solution to make a 25% acid solution. This can be calculated using a dilution formula: initial acid amount / final total amount = final acid concentration.
How do you get a 5 percent diluted acetic acid from a 99 percent acetic acid solution?
To make a 5% diluted acetic acid solution, you would mix 1 part of the 99% acetic acid solution with 19 parts of water (since 1 part acetic acid solution + 19 parts water = 20 parts total solution, and 1/20 = 5%). This will result in a 5% acetic acid solution.
How much pure acid should be added to 50 ml of a 10 percent acid solution to give a 50 percent acid solution?
A 50 ml solution that is 10% acid will consist of 5 ml of acid (10% of the volume) and 45 ml of water (90% of the volume). You're not adding any water, but you want to add enough acid to make a solution that is 50% acid and 50% water. You will need to have a total of 45 ml of acid in the mixture to make it a 50/50 solution, since the amount of water is also 45 ml. You have 5 ml in there already, so you would need to add 40 ml of acid. That would make a total 90 ml solution that is 50% water (45 ml) and 50% acid (45 ml).
How do you make a 2.5 percent acetic acid solution from a 33 percent solution?
so it is 33% already. You need to dilute every 33ml with 30.5ml solvent and adding 2.5ml of the solution. Feel free to message if you need further explaining
How many grams of acetic acid should be dissolved in 100 g of water to make a 4.0 percent solution of vinegar?
To make a 4.0% solution of vinegar, 4.0 g of acetic acid should be dissolved in 100 g of water.
How do I produce a 4 percent citric acid solution using 50 percent citric acid powder and distilled water?
To produce a 4% citric acid solution, you can mix 1 part of 50% citric acid powder with 11 parts of distilled water. For example, mix 1 mL of the citric acid powder with 11 mL of distilled water. This will give you a total of 12 mL of 4% citric acid solution.
How do you make a Molar solution from 32 percent hydrochloric acid?
To make a molar solution from a 32% hydrochloric acid solution, you would need to first calculate the molarity of the 32% solution. Molarity is calculated by multiplying the percent concentration by the density of the solution and dividing by the molar mass of the solute. Once you determine the molarity, you can then dilute the solution to the desired molar concentration by adding the appropriate amount of solvent (usually water).
