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A chemist has one solution which is 50 percent acid and a second solution which is 25 percent acid how much of each should be mixed to make a 10 liters of a 40 percent acid solution?
6 litres of 50% + 4 litres of 25%
How many liters of water must be added to 7 liters of a 20 percent acid solution to obtain a 10 percent acid solution?
7 liters of a 20% acid solution consists of 1.4 liters of acid (20% of the total volume) mixed with 5.6 liters of water (80% of the total volume). The amount of acid isn't going to change in the new solution. You are just going to add enough water to make it a 10% solution instead of a 20% solution. So it will be more dilute. That means that 1.4 liters of acid will represent 1/10 of the volume of the new solution. So the total volume of the new solution will be 10 x 1.4 or 14 liters. The amount of water in the new solution will be 14 - 1.4 = 12.6 liters. That is a difference of 12.6 - 5.6 = 7 liters from the amount of water you started with. So you need to add 7 liters of water to the original 20% solution to make it a 10% solution. This makes sense because if you double the amount of the mixture from 7 liters to 14 liters and the amount of acid is unchanged, the solution will be half as strong.
How many liters of water must be added to 30 liters of 20 percent ALCOHOL solution to dilute it to a15 percent solution?
You have 6 litres of alcohol in 24 litres of water You need to add x litres to make 6 equal to 15% of 30 + x. 6 is 15% of 40, so x = 10
How can we convert 25 percent of ammonia solution to 10 M?
25% ammonia solution means 25g Ammonia in 100ml of water. To convert it into moles i.e for 1000ml solvent, 25x100=250 which means 250g of ammonia is present in 1000ml of water to make a 25%solution. To convert it into molar solution we will divide 250 by the molecular mass of ammonia i.e 17. 250/17= 14.71M This means that 25% ammonia solution contains 14.71 moles of ammonia. Now we will use the formula M1V1=M2V2 Let's say we want to make 10 molar solution in 500ml water. Then, M1=14.71 V1=? M2=10 V2=500 Putting values in the above equation: 14.71xV1 = 10x500 V1 = 10x500 / 14.71 = 340ml We will take 340ml of the 25% ammonia solution and make the volume up to 500ml with water. This will be our 10 molar solution of Ammonia.
What is a number that can replace a variable to make an equation true?
solution
