40 fl oz of the 16% solution and 24 of the other.
(Note: This answer assumes that the "ounces" specified are avoirdupois or other weight ounces and that percentages are by weight; otherwise possible volume changes on dilution must by considered.) The weight of pure alcohol in each solution is the product of the percentage and the total weight of the solution. Therefore, designating the unknown weight of 30 % alcohol as w, from the problem statement 0.30w + 0.80(40) = 0.70(w + 40), or 0.30w + 32 = 0.70w + 28, or 32 - 28 = w(0.70 - 0.30) or w = 4/0.40 = 10 ounces of 30 % alcohol.
In liquid ounces: 5 ounces = 1/2 a cup + 1 ounce 8 ounces = cup 16 ounces = pint 32 ounces = quart 64 ounces = half gallon 128 ounces = gallon --- In weight ounces: 5 ounces = 1/4 pound + 1 ounce 16 ounces = 1 pound
The metric conversion of 1.25 gallons to ounces is 160 ounces. This measurement can also be further converted to 20 cups.
well i think its 4 ounces wait i dont need to think it is 4 ounces
That would be a quarter of a cup or 1/4 of a cup
4 ounces
(Note: This answer assumes that the "ounces" specified are avoirdupois or other weight ounces and that percentages are by weight; otherwise possible volume changes on dilution must by considered.) The weight of pure alcohol in each solution is the product of the percentage and the total weight of the solution. Therefore, designating the unknown weight of 30 % alcohol as w, from the problem statement 0.30w + 0.80(40) = 0.70(w + 40), or 0.30w + 32 = 0.70w + 28, or 32 - 28 = w(0.70 - 0.30) or w = 4/0.40 = 10 ounces of 30 % alcohol.
Let a be the number of ounces of 25% alcohol required. Then, 25a + (30x9) = 28(9 + a) 25a + 270 = 252 + 28a 3a = 18 a = 6 Then 6 ounces of 25% alcohol + 9 ounces of 30% alcohol produces 15 ounces of 28% alcohol.
Let x be the ounces of 15% alcohol solution. The amount of alcohol in the 15% solution is 0.15x, and the amount of alcohol in the 23% solution is 0.23(100 - x). Setting up the equation 0.15x + 0.23(100 - x) = 0.15(100) solves for x, which is approximately 38.5 ounces of the 15% alcohol solution needed.
Let x = ounces of 50% solution, and y = ounces of 1% solution. So that we have: 0.5x + 0.01y = 8(0.2) which is a linear equation in two variables, meaning there are infinitely many choices of mixing those solutions.
.35x+.40*14=0.37(x+14) .35x=.37x-5.6+5.18 .35x=.37x-.42 -.02x=.42 x=21 check 21*.35+14*.4=7.35+5.6=12.95 12.95/(14+21)=.37 so you would need 21 ounces of 0.35 mixed in with 14 ounces of 40 % to get a 37% solution of which you would have 35 ounces
Yes, alcohol can be measured in ounces. This is because one standard serving of alcohol is typically around 1.5 ounces.
1.5 ounces of 40% alcohol is equal to 12 ounces of 5% alcohol. So no they are both the same.
two ounces
1.5 ounces
No, four ounces of wine and four ounces of whiskey will not have the same alcohol content. Whiskey generally has a higher alcohol by volume (ABV) than wine, so four ounces of whiskey will have more alcohol than four ounces of wine.
10 ounces