answersLogoWhite

0

Let x = ounces of 50% solution, and y = ounces of 1% solution. So that we have: 0.5x + 0.01y = 8(0.2) which is a linear equation in two variables, meaning there are infinitely many choices of mixing those solutions.

User Avatar

Wiki User

11y ago

What else can I help you with?

Related Questions

How many ml of water should be added to 95 percent ethyl alcohol to make 1 liter of a 30 percent ethyl alcohol solution?

684 ml


How much water should be mixed to 12ml of alcohol to obtain a 12 percent of alcohol solution?

To obtain a 12% alcohol solution, you would need to mix 12ml of alcohol with 48ml of water. This would give you a total volume of 60ml, with 12% of it being alcohol.


How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?

How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?


How much of a ten percent solution should be added to two cups of twenty percent solution to make a twelve percent solution?

2%


What fraction of 10 percent alcohol should be mixed with 70 percent alcohol to obtain 50 percent alcohol?

2/3 of 70% and 1/3 of 10%


How much of an alloy that is 40 percent copper should be mixed with 400 ounces of an alloy that is 70 percent copper in order to get an alloy that is 50 percent copper?

200 ounces.


How many liters of a 20 percent solution of acid should be added to 10 liters of a 30 percent solution of acid to obtain a 25 percent solution?

10 liters.


Which solution should the technician use to clean the contacts?

rubbing alcohol


How much of an alloy that is 10 percent copper should be mixed with 400 ounces of an alloy that is 70 percent copper in order to get an alloy that is 20 percent?

How much of an alloy that is 10% copper should be mixed with 400 ounces of an alloy that is 70% copper in order to get an alloy that is 20%


A 280 mL solution is 20 percent salt How much water should be added to make the solution 14 percent salt?

98 mL


How much water should be added to 16ml of 9 percent alcohol solution to reduce the concentration to 8 percent?

The way I would do this is to first determine the amount of alcohol and that would be 0.09 x 16 ml = 1.44 ml then I would ask myself (0.08 * x) = 1.44 Therefore to have an 8% solution we would have a total of 18 ml of solution (by solving the above equation), thus we would have to add 2 ml of water (18 ml - 16 ml).


If you have a 300ml of a 15 percent hydrochloric acid solution in dilute the solution to 1000ml with sterile water what percent should appear on the label?

The concentration of the diluted solution will be 15(300/1000) = 4.5 %, if the percent is expressed on a weight/volume basis.