possibly than 20,
3040
3041 etc
3050
3051 etc
The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2. 5
Write them as decimals, and compare. If the first digit of two numbers is equal, compare the second digit; if the second digit is equal, compare the third digit, etc.
The first digit has 4 choices for its digit. The second digit has 6 choices and the third has 3. The solution would simply be 4*6*3=72 three digit numbers.
There are 9 choices for the first digit (1,2,3,4,5,6,7,8,9) No zero because numbers don't start with zeroes. 10 choices for the second digit (0,1,2,3,4,5,6,7,8,9). 10 choices for the third digit (0,1,2,3,4,5,6,7,8,9) Okay now 9x10x10=900. Answer:900
That makes:* 8 options for the first digit * 8 options for second digit * 10 options for the third digit * ... etc. Just multiply all the numbers together.
A positive number is greater than a negative number. If a positive number is greater than another, the corresponding negative numbers are smaller. For example, since 4 > 3, -4 < -3. For two positive numbers: The number with more digits is greater. If they have the same number of digits, the number with the greater first digit is greater. If they are equal, look at the second digit, which will decide which number is greater, and so forth, up to the last digit. For example, 12500 is greater than 12480: they have the same number of digits, the first two digits are the same, but the third digit is the tie-breaker. For numbers with decimals, first apply the rules above for the whole part. If they are equal, check the first digit after the decimal point, then the second, etc., until you find a "tie-breaker". For example, 0.2522 is more than 0.2517. Once again, the first two digits are the same, the third is the tiebreaker.
You can select 12 numbers for the first digit, 11 numbers for the second digit, and 10 numbers for the third digit; so 12*11*10 = 1320 sets of 3 numbers can be made out of 12 different numbers.
1348.
4284
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.
3 digit positive even numbers is: 9 x 10 x 5 = 450 because in the first spot you can have 1-9 (9 possibilities) , the second spot 0-9 (10 possibilities), and the third you can have 0, 2, 4, 6, 8 (5 possibilities).