None.
Whatever number you substitute for 'x', 0x will always be 0,
and the equation will always become [ 0 = 4 ].
No value of 'x' can make [ 0 = 4 ]. There is no solution.
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x2 - 21x = 72x2 - 21x - 72 = 0(x - 24) (x + 3) = 0x = 24x = -3
x2-14x+45=0(x-9)(x-5)=0x-9=0 & x-5=0x=9 & x=5
This is always true! According to the Additive Inverse Axiom -X+X always equals 0 which is equivalent to 0X.
x2 = 8xx2- 8x = 0x(x - 8) = 0x = 0 ;x - 8 = 0x = 8
x+(-2.5)+6.8=0x+(-2.5+6.8)=0x+(4.3)=0x+4.3=0Subtract 4.3 from both sides and you get:x= -4.3