5x5x6=150
If the cube has 5 inch long sides then each side has an area of 5 inches x 5 inches which equals 25 sqare inches. The cube has 6 sides so the total area of paper needed to cover it is 25 square inches x 6, which is 150 square inches of paper.
144
52 square inches for each layer, minimum with no overlap anywhere.
The perimeter of a square is 100 inches. How many square tiles 1 inch on each edge are needed to cover its area?
Surface area of box: (2*6*4)+(2*6*2)+(2*4*2) = 88 square inches of gift wrap will be needed
Well, honey, to wrap that rectangular prism, you gotta find the surface area. Add up the area of all six sides: 2(8x8) + 2(8x10) + 2(8x10) = 320 square inches. So, you'll need at least 320 square inches of wrapping paper to cover that bad boy.
144
To cover a rectangle that measures 6 inches by 4 inches, you would first calculate the area of the rectangle, which is 6 inches × 4 inches = 24 square inches. Since each 1-inch square covers 1 square inch, you would need 24 of the 1-inch squares to completely cover the rectangle.
my room is ; 124 INCHES X 104 INCHES HOW MANY SQUARE METERS OF CARPET DO I NEED TO COVER IT?
184.08 square feet is needed.
How many squares with sides that are 6 inches long I needed to cover a square with a side length of 30 inches without overlapping
2880 exactly, but if this is ceramic tiles you have to account for grout lines. extras would be recommended
5 ft by 9 ft is 45 square feet. This requires 6,480 square inches to cover it.
17 (16.65) square meters are needed, at minimum.
One side of a square is 10 inches long. How many one square inch tiles are needed to cover its area?
195 12 inches x 12 inches is 1 square foot
52 square inches for each layer, minimum with no overlap anywhere.
54