52 square inches for each layer, minimum with no overlap anywhere.
Well, honey, to wrap that rectangular prism, you gotta find the surface area. Add up the area of all six sides: 2(8x8) + 2(8x10) + 2(8x10) = 320 square inches. So, you'll need at least 320 square inches of wrapping paper to cover that bad boy.
144
The perimeter of a square is 100 inches. How many square tiles 1 inch on each edge are needed to cover its area?
5x5x6=150 If the cube has 5 inch long sides then each side has an area of 5 inches x 5 inches which equals 25 sqare inches. The cube has 6 sides so the total area of paper needed to cover it is 25 square inches x 6, which is 150 square inches of paper.
Surface area of box: (2*6*4)+(2*6*2)+(2*4*2) = 88 square inches of gift wrap will be needed
Well, honey, to wrap that rectangular prism, you gotta find the surface area. Add up the area of all six sides: 2(8x8) + 2(8x10) + 2(8x10) = 320 square inches. So, you'll need at least 320 square inches of wrapping paper to cover that bad boy.
2(8)(10) + 2(8)(8) + 2(10)(8) 160 + 256 + 160 320 + 256 576 in. square
you COULD completely cover the box with 88 square feet of paper, it would look pretty ugly because you would have to tape every edge though ;) btw, 88 sq ft is 12,672 square inches.
12" x 8" = 96 square inches
Approximately 16.33 square feet.
144
184.08 square feet is needed.
the answer is 6 by 8=28********************************6 inches x 8 inches = 48 square inches
Each tile will cover 100 square inches. 12,000 square feet is 1,728,000 square inches. You will need 17,280 tiles.
How many squares with sides that are 6 inches long I needed to cover a square with a side length of 30 inches without overlapping
195 12 inches x 12 inches is 1 square foot
just think when was the first time that anybody needed this, huh??