0
The first digit must be 7 or greater, because the digits of 699 only sum to 24.
Of the numbers beginning with 7, only 799 sums to 25, because if either of the other two digits are less than 9, the sum will be less than 25.
That's one so far.
For number beginning with 8, the other two digits must sum to 17. That means they must be 9 and 8. So there are two suitable numbers beginning with 8, namely 889 and 898.
That's a total of three so far.
Finally, we have numbers beginning with 9. The other two digits must sum to 16, so the candidates are: 9 and 7, or 8 and 8. That gives us three numbers that fit the bill: 997, 979 and 988.
That's six altogether.
So the answer is six.
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How many four digit whole numbers are there such that the thousand digit is odd the hundreds digit is even and all four digits are different?
5*5*4*4 = 400
How many whole numbers have exactly 3 digits hint 999 is the greatest whole number with three digitsint999?
The smallest such number is 100, the largest is 999, so the size of this set is:999 - 100 + 1 Another way to solve this: You have: * 9 options for the first digit * 10 options for the second digit * 10 options for the third digit Multiply all these numbers together.
What is a 3 digit number that all its digits are odd and add up to 7?
10
Whole no between 1 and 100 use the digit 6 at least once?
use the digit 1234to make two different numbers
How many 2's whole numbers between 0 and 99 contain the digit?
greatest two digit number is 99. smallest whole number is 0 there fore 99-0=99
