The first digit must be 7 or greater, because the digits of 699 only sum to 24.
Of the numbers beginning with 7, only 799 sums to 25, because if either of the other two digits are less than 9, the sum will be less than 25.
That's one so far.
For number beginning with 8, the other two digits must sum to 17. That means they must be 9 and 8. So there are two suitable numbers beginning with 8, namely 889 and 898.
That's a total of three so far.
Finally, we have numbers beginning with 9. The other two digits must sum to 16, so the candidates are: 9 and 7, or 8 and 8. That gives us three numbers that fit the bill: 997, 979 and 988.
That's six altogether.
So the answer is six.
5*5*4*4 = 400
The smallest such number is 100, the largest is 999, so the size of this set is:999 - 100 + 1 Another way to solve this: You have: * 9 options for the first digit * 10 options for the second digit * 10 options for the third digit Multiply all these numbers together.
10
use the digit 1234to make two different numbers
greatest two digit number is 99. smallest whole number is 0 there fore 99-0=99
All five digit numbers have three digits. The smallest five digit whole number is 10,000
there are 899 whole numbers that have three digits.
7 two-digit numbers.
-4309278
There are only 999 three digit whole numbers.
There are no 3-digit whole numbers whose digits sum to 3. The smallest 3-digit number is 100, and the largest is 999, but in neither case is the sum of the digits equal to 3.
There are no three-digit numbers that equal 17. In fact, there are no numbers with more or less than two digits that equal 17. In fact, in the whole infinite supply of numbers, there is only one single number that equals 17. That number is . . . . . . . 17 .
4,536 whole numbers or mixed numbers. 5,040 pure decimals.
-21
Among whole numbers, 1,023,456 is.
There are 900 three-digit whole numbers between 1 and 1000
Yes.