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How many triangles in a 16 sided polygon?

Updated: 4/28/2022
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Niallynoo

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Q: How many triangles in a 16 sided polygon?
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Continue Learning about Algebra

How many triangles are in a 32 side polygon?

A 32 sided polygon is also called a triacontadigon (or triacontakaidigon) or 32-gon has 20 triangles and 12 pentagons.


How many triangles in the large triangle?

If you are talking about the common triangle puzzle, then there are 27 triangles. There are 16 one-cell triangles, 7 four-cell triangles, 3 nine-cell triangles, and 1 sixteen-cell triangle. There is a link to the pic for you also. _______________________________________________________________________ The answer in a two dimensional way would be 27. However, if you take into account that each triangle can be turned three ways, then you can understand that there are actually 81 triangles in all. THen you could ask the question, how many triangles can fit in this space (i.e. the picture)? The answer is the first level of infinitely many, or Aleph zero. This would be by finding the midpoint of each side of the all the 1- cell triangles and creating a new triangle.


How can you remove 4 toothpicks from 16 toothpicks to get 4 congruent triangles?

Fuor toothpicks from 16 leave 12 which, by coincidence (?) is exactly enough for four equilateral triangles!


If the measure of a polygon is 16 cm by 24 cm what is the measure of a polygon half the size?

8 x 24? 16 x 12? 6 x 32? etc etc


What is the area of a regular nonagon with a perimeter of 144 inches?

A nonagon is a nine-sided polygon. The area of a regular polygon is:A = (n/4)(s^2)[cos (180° /n)]/[sin (180° /n)]So the area of the nonagon with side 16 (144/9) is:A = (9/4)(16^2)[[cos(180°/9)]/[sin (180°/9)]]= (2.25)(256)[(cos 20°)/(sin 20°)]A ≈ 1,582.55 ft^2 If you don't know the formula of the area of a polygon, you can find its area by multiplying by 9 the area of one of the 9 congruent isosceles triangles that are formed by connecting the center of the polygon with its vertices. But for this you need to find the altitude and the length of the side (which is the radius of the circumscribed circle) of that triangle such as:we know the length base which is 16 ft (144/9), the angle base which is 70 (140/2), and the vertex angle which is 40 (360°/9 or 180° - 140°). By using the Law of Sines we can find the length of r. So,r/sin 70° = 16/sin 40° multiply by sin 70° to both sides;r = (16 sin 70°)/sin 40° sin 70 = altitude/radiusaltitude = (sin 70)(radius) = (Sin 70)[(16 sin 70)/sin 40]altitude = [16(sin 70)^2]/sin 40Thus the area of this nonagon is:A = 9[(1/2)(bh)] where b = 16 and h = [16(sin 70)^2]/sin 40A = (4.5)(16) [[16(sin 70)^2]/sin 40] A ≈ 1,582.55 ft^2